# Mathematics Formula for Competitive Exam PDF

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## Mathematics Formula for Competitive Exam

The mathematical formula is one of the most important things in exams. Time is the main factor in competitive exams. If you manage your time then you can do well in those exams. That doesn’t mean that other topics are less important. But, if you need a good score in the exam then you have to score well in maths. A good score comes with practice and practice. The only thing you need to do is to do your math problems correctly and within time, and you can do this only by using shortcut tricks.

• Number sets
• Algebra
• Geometry
• Trigonometry
• Matrix and determinant
• Vectors
• Analytic Geometry
• Differential calculus
• Integral Calculus
• Differential Equations
• Series

### मैथ के फार्मूला – Math Formula Hindi

• (α+в)²= α²+2αв+в²
• (α+в)²= (α-в)²+4αв b
• (α-в)²= α²-2αв+в²
• (α-в)²= f(α+в)²-4αв
• α² + в²= (α+в)² – 2αв
• α² + в²= (α-в)² + 2αв
• α²-в² =(α + в)(α – в)
• 2(α² + в²) = (α+ в)² + (α – в)²
• 4αв = (α + в)² -(α-в)²
• αв ={(α+в)/2}²-{(α-в)/2}²
• (α + в + ¢)² = α² + в² + ¢² + 2(αв + в¢ + ¢α)
• (α + в)³ = α³ + 3α²в + 3αв² + в³
• (α + в)³ = α³ + в³ + 3αв(α + в)
• (α-в)³=α³-3α²в+3αв²-в³
• α³ + в³ = (α + в) (α² -αв + в²)
• α³ + в³ = (α+ в)³ -3αв(α+ в)
• α³ -в³ = (α -в) (α² + αв + в²)
• α³ -в³ = (α-в)³ + 3αв(α-в)

#### Speed, Distance & Time

• Speed = distance/time
• Time = distance/ Speed
• Distance = (Speed * Time)
• Distance = Rate x Time
• Rate = Distance/Time
• Convert from kph (km/h) to mps(m/sec):
x km/hr=x∗(5/18) m/sec
• Convert from mps(m/sec) to kph(km/h):
x m/sec= X*(18/5) km/h
• If the ratio of the speeds of A and B is a: b, then the ratio of the times taken by them to cover the same distance is 1/a: 1/b or b: a • Suppose a man covers a certain distance at x km/hr and an equal distance at y km/hr. Then, the average speed during the whole journey is:- 2xy/(x + y)
• When speed is the constant distance covered by the object is directly proportional to the time taken. ie; If Sa=Sb then Da/Db = Ta/Tb
• When time is constant speed is directly proportional to the distance travelled. ie; If Ta=Tb then Sa/Sb=Da/Db
• When the distance is constant speed is inversely proportional to the time taken ie if speed increases then time is taken to cover the distance decreases. ie; If Da=Db then Sa/Sb = Tb/Ta
• If the speeds given are in Harmonic progression or HP then the corresponding time taken will be in Arithmetic progression or AP
• If the speeds given are in AP then the corresponding time taken is in HP
• If two objects are moving in the same direction with speeds a and b then their relative speed is |a-b|
• If two objects are moving in the opposite direction with speeds a and b then their relative speed is (a+b)

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